A system absorbs 800 joules of energy and does of work of 200 joules change in internal energy of the process is
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a
+ 600 J
b
- 600 J
c
+ 1000 J
d
- 1000 J
answer is A.
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Detailed Solution
By IUPAC conventionHeat absorbed by the system = +VeHeat absorbed by the system = +800 JWork done by the system = -VeWork done by the system = -200 J∆E= (+800 - 200) J∆E = +600 J .