Q.
A system absorbs 10 KJ of heat at constant volume and its temperature rises from 270C to 370C. The ΔE of reaction is
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a
100KJ
b
10KJ
c
0
d
1KJ
answer is B.
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Detailed Solution
ΔE = q+W = q+(-PΔV)Δv = 0 ;ΔE = qv = 10KJ
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