Q.

A system absorbs 10 KJ of heat at constant volume and its temperature rises from 270C to 370C. The ΔE of reaction is

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a

100KJ

b

10KJ

c

0

d

1KJ

answer is B.

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Detailed Solution

ΔE = q+W = q+(-PΔV)Δv = 0 ;ΔE = qv = 10KJ
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