First slide

Gibb's Helmholtz equation

Question

For a system at 300 K, change in enthalpy is $60 kJ . {mol}^{- 1}$ and change in entropy is $300 J . K^{- 1} . {mol}^{- 1}$ . Gibbs free energy of the system at that temperature will be

Moderate

A

-30J/mole
B

+30J/mole
C

-30kJ/mole
D

+30kJ/mole

Solution

$∆ G = ∆ H - T ∆ S; ∆ G = (60 kJ . {mol}^{- 1}) - (300 K) (0.3 kJ . K^{- 1} {mol}^{- 1}); ∆ G = - 30 kJ / mole$

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