First slide

Gibb's Helmholtz equation

Question

For a system at 300 K, change in enthalpy is $60 kJ . {mol}^{- 1}$ and change in entropy is $200 J . K^{- 1} . {mol}^{- 1}$ . Gibbs free energy of the system at that temperature will be

Moderate

A

Zero
B

+20J/mole
C

-30kJ/mole
D

+120kJ/mole

Solution

$∆ G = ∆ H - T ∆ S; ∆ G = (60 kJ . {mol}^{- 1}) - (300 K) (0.2 kJ . K^{- 1} {mol}^{- 1}); ∆ G = zero;$

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