First slide

First law of thermo dynamics

Question

A system liberates 400 Joules of heat and does 600 Joules of work. Change in internal energy for the process is

Easy

A

+1000 J
B

-1000 J
C

-200 J
D

+200 J

Solution

Heat liberated by the system = -400 J
Work done by the system = -600 J
$∆$ E = (-400 -600)J
$∆$ E = -1000 J

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