Q.

In a system A(s)⇌2B(g)+3C(g) if the concentration of C at equilibrium is increased by a factor of 2, it will cause the equilibrium concentration of B to change to :

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two times the original value

one half of its original value

22 times to the original value

122 times the original value

answer is D.

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Detailed Solution

KC=[B]2[C]3 and KC remains constant. A(s)⇌2B(g)+3C(g)∴Kc=[C]3[B]2If [C] becomes twice, let [B] become [B'], thenKc=(2C)3(B′)2 or [C]3[B]2=(2C)3(B′)2 ∴B'B=18=122

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