The heat of neutralization of oxalic acid is -25.4 k.cal. mol−1 using strong base NaOH then the enthaphy change of the process isH2C2O4⇌ 2H++C2O4−2
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a
2 k.cal
b
-11.8 k. cal
c
1.0 k.cal
d
-1.0 k. cal
answer is A.
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Detailed Solution
Oxalic acid has two ionisable H+ hence expected heat of neutralization, If it behaves as a strong acid would have been =−13.7×2=−27.4 k.cal mol−1But experimental value =−25.4 k.cal.mol−1Heat of ionization =27.4−25.4=2k.cal/ mol