First slide

Kinetics of nuclear reactions or nuclear chemistry

Question

$A \frac{T_{50} = 100 \min}{N_{A}} B \frac{T_{75} = 100 \min}{N_{B}} ⟶ C$
At equilibrium $\frac{N_{A}}{N_{B}}$ is

Moderate

A

1
B

2
C

0.5
D

20

Solution

$N_{A} T_{50} (B) = N_{B} T_{50} (A)$
$T_{50} (B) = \frac{T_{75} (B)}{2} = \frac{100}{2} = 50 \min; \frac{N_{A}}{N_{B}} = \frac{100}{50} = 2$

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