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The temperature of 1000 gram's N₂ is increased from 20°C to 100°C (at constant P). (specific heat at constant volume C_v = 5 cal/mol ⁰C)
Then the correct statement(s) is / are

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Heat required in the process is 30 kcal

Increase in the internal energy of Gas is 21 Kcal

If process is at constant volume then heat required is 21 kcal

External work done is 110 Kcal.

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detailed solution

Correct option is A

1) Q = nCp ∆T ⇒(Cv+R)∆T⇒1000285+2×120 Q = 30×103 cal ⇒30 kcal2) ∆U=nCv∆T⇒100028×5×120⇒21 Kcal3) Q=nCv∆T+P∆V for constant V, ∆V=0 Q=nCv∆T⇒21 kcal4) External work done is W = Q - ∆U=9 Kcal.

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The temperature of 1000 gram's N2 is increased from 20°C to 100°C (at constant P). (specific heat at constant volume Cv = 5 cal/mol 0C)Then the correct statement(s) is / are

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The temperature of 1000 gram's N₂ is increased from 20°C to 100°C (at constant P). (specific heat at constant volume C_v = 5 cal/mol ⁰C)
Then the correct statement(s) is / are