The temperature of an ideal gas is increased from 140 K to 560 K. If at 140 K the root mean square velocity of the gas molecule is V, at 560 K it becomes
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a
5V
b
2V
c
V/2
d
V/4
answer is B.
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Detailed Solution
The Vrms at 140K is V∴ V=3R × 140M At 540 K , V' = 3R × 560M =3R × 140 × 4M = 2 3R × 140M=2V