The temperature at which 10% aqueous solution (w/V) of glucose exhibits the osmotic pressure of 16.4 atm, is (R = 0.082 dm3 atm K-1mol-1)

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200 K

180 K

90 K

360 K

answer is D.

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Detailed Solution

We know that osmotic pressure, π=CRT=w×R×Tm×V 16.4=10×1000180×100×0.082×T ∴T=16.4×1800.082×100=360 K

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