2, 2, 3, 3-tetrabromo butane →∆Zn/C2H5OHX ; Number of linear atoms in the compound ‘X’ are
0
2
1
4
CH3-CBr2-CBr2-CH3+2Zn→∆C2H5OHCH3-C≡C-CH3+2ZnBr2All the four carbon atoms are linear atoms.