There are two samples of H and $$He+$$ atom. Both are in some excited state. In hydrogen atom, total number of lines observed in Balmer series is $$4$$ and in $$He+$$ atom total number of lines observed in Paschen series is $$1$$. Electron in hydrogen sample make transitions to lower states from its excited state, then the photon corresponding to the line of maximum energy line of Balmer series of H sample is used to further excite the already excited $$He+$$ sample. Then maximum excitation level of $$He+$$ sample will be

Question

There are two samples of H and $$He+$$ atom. Both are in some excited state. In hydrogen atom, total number of lines observed in Balmer series is $$4$$ and in $$He+$$ atom total number of lines observed in Paschen series is $$1$$. Electron in hydrogen sample make transitions to lower states from its excited state, then the photon corresponding to the line of maximum energy line of Balmer series of H sample is used to further excite the already excited $$He+$$ sample. Then maximum excitation level of $$He+$$ sample will be

Infinity Learn · Accepted Answer

In $$H-atom$$, $$4$$ lines are observed in Balmer series. So, electron is in n $$=$$ $$6$$ $$6$$→$$2$$,  $$5$$→$$2$$,  $$4$$→$$2$$,  $$3$$→$$2$$. In $$He+$$ ion, one line is observed in  Paschen  series. So electron is in n $$=$$ $$4$$ $$4$$→$$3$$.$$H6$$→$$2$$  $$=$$  Hen→$$4H6$$→$$2$$  $$=$$  $$He+12$$→$$4$$∴    electron   in  $$He+$$  will  jump  from  $$n=4$$  to  $$n=12$$.

Best Courses for You

Detailed Solution

courses

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

download the app

Download the App