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Q.

For thereaction,   ,   if one mole of   oxidises 1.67 moles of Mx+ to MO3- , then the value of 'x' in the reaction is

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answer is 3.

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Detailed Solution

Increase in Ox.state for 1.67 mole of M+x = (5-x) 1.67Total decrease in Ox.state = total increase in Ox.state5 = (5-x)1.675 = 8.35 - 1.67x1.67x = 3.35X = 2
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For thereaction,   ,   if one mole of   oxidises 1.67 moles of Mx+ to MO3- , then the value of 'x' in the reaction is