Thermal decomposition of gaseous $$X2$$ to gaseous X at $$298$$ K takes place according to the following equation: $$X2g$$⇌ $$2Xg$$.The standard reaction Gibbs energy, Δ$$rG0$$,of this reaction is positive. At the start of the reaction, there is one mole of $$X2$$ and no X. As the reaction proceeds, the number of moles of X formed is given by b. Thus, βequilibrium is the number of moles of X formed at equilibrium . The reaction is carried out at a constant total pressure of $$2$$ bar. Consider the gases to behave ideally. (Given$$ : $$R=0.083$$ L bar K−$$1mol$$−$$1) The equilibrium constant KP for this reaction at $$298$$ K, in terms of βequilibrium isThe INCORRECT statement among the following , for this reaction, is

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Thermal decomposition of gaseous $$X2$$ to gaseous X at $$298$$ K takes place according to the following equation: $$X2g$$⇌ $$2Xg$$.The standard reaction Gibbs energy, Δ$$rG0$$,of this reaction is positive. At the start of the reaction, there is one mole of $$X2$$ and no X. As the reaction proceeds, the number of moles of  X formed is given by b. Thus, βequilibrium is the number of moles of  X formed  at equilibrium . The reaction is carried out at a constant total pressure of $$2$$ bar. Consider the gases to behave ideally. (Given$$ : $$R=0.083$$ L bar K−$$1mol$$−$$1) The equilibrium constant KP for this reaction at $$298$$ K, in terms of βequilibrium isThe INCORRECT statement among the following , for this reaction, is

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$$X2$$⇌$$2x$$,                   Δ  $$=ve1$$                                         $$01$$−β$$2$$                         β$$Px2=1$$−β$$21+$$β$$2x2=2$$−β$$2+$$β×$$2Px=$$β$$1+$$β$$2.2=4$$β$$2+$$β$$kp=4$$β$$2+$$β$$22$$−β$$2+$$β$$.2=16$$β$$22+$$β$$22+$$β$$22$$−β$$=8$$β$$24$$−β$$2$$β value cannot be calculated,

Chemical Equilibrium

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The equilibrium constant K_P for this reaction at 298 K, in terms of $β_{e q u i l i b r i u m}$ is

The INCORRECT statement among the following , for this reaction, is

$β$ value cannot be calculated,

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