First slide

Faraday's Laws

Question

Time required to deposit one millimole of aluminium metal by the passage of 9.65 amperes through aqueous solution of aluminium ions is

Easy

A

30 s
B

10 s
C

30,000 s
D

10,000 s

Solution

mass of 1 milli mole of Al =27 x 10^-3 gm
GEW of Al =27/3=9
$m = \frac{{Eit}}{{96500}}$
$t = \frac{{96500m}}{{Ei}} = \frac{{96500 \times 27 \times {{10}^{ - 3}}}}{{9 \times 9.65}} = 30\sec$

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