Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Titanium metal is extensively used in aerospace industry because the metal imparts strength to structures but does not unduly add to their masses. The metal is produced by the reduction of TiCl4(l) which in turn is produced from mineral rutile TiO2(s). The following reaction for production of TiCl4⁡(ℓ) be carried out at 25∘C:TiO2(s)+2Cl2(g)⟶TiCl4(ℓ)+O2(g). Given that ΔHf0 for TiO2(s),TiCl4⁡(ℓ),Cl2(g) and O2(g) is −944.7,−804.2,0.0,0.0KJmol−1⋅S∘  respectively for TiO2(s),TiCl4(ℓ),Cl2(g) and O2(g) is 50.3,252.3,233.0,205.1Jmol−1K−1 respectively. Select correct options from the following.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

ΔHr∘>0

b

ΔSr∘>0

c

ΔGr∘>0

d

Reaction is not possible under standard conditions

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Titanium metal isΔHr∘=140.5kJΔSr0=−0.058kJΔGr∘>0
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring