Toluene in the vapour phase is in equilibrium with a solution of benzene and toluene having mole fraction of toluene $$0.50$$. If vapour pressure of pure benzene is $$119$$ torr and that of toluene is $$37.0$$ torr at the same temperature, mole fraction of toluene in vapour phase will be :

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Given $$pbenzene0$$  $$=$$  $$119$$  torr ; $$ptoluene0=$$  $$37$$  torrXtoluene  $$=$$ Xbenzene  $$=$$  $$0.5(X$$ $$=$$ M.F. in liquid $$phase)According$$ to Raoult’s LawPtotal $$=$$    $$pA0XA$$  $$+$$  $$pB0$$  XB               $$=$$ $$119(0.5)$$  $$+$$  $$37(0.5)In$$ Vapour  phase  Applying Dalton’s Lawptoluene  $$=$$ Ttotal  ×    ytoluene $$(Y$$ $$=$$ M.F. in vapour $$phase)ytoluene$$     $$=$$  ptoluenePtotal   $$=$$  $$370.51190.5$$  $$+$$  $$370.5$$  $$=$$  $$0.237$$

Toluene in the vapour phase is in equilibrium with a solution of benzene and toluene having mole fraction of toluene 0.50. If vapour pressure of pure benzene is 119 torr and that of toluene is 37.0 torr at the same temperature, mole fraction of toluene in vapour phase will be :

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