Toluene in the vapour phase is in equilibrium with a solution of benzene and toluene having mole fraction of toluene $$0.50$$. If vapour pressure of pure benzene is $$119$$ torr and that of toluene is $$37.0$$ torr at the same temperature, mole fraction of toluene in vapour phase will be :

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Infinity Learn · Accepted Answer

Given $$pbenzene0$$  $$=$$  $$119$$  torr ; $$ptoluene0=$$  $$37$$  torrXtoluene  $$=$$ Xbenzene  $$=$$  $$0.5(X$$ $$=$$ M.F. in liquid $$phase)According$$ to Raoult’s LawPtotal $$=$$    $$pA0XA$$  $$+$$  $$pB0$$  XB               $$=$$ $$119(0.5)$$  $$+$$  $$37(0.5)In$$ Vapour  phase  Applying Dalton’s Lawptoluene  $$=$$ Ttotal  ×    ytoluene $$(Y$$ $$=$$ M.F. in vapour $$phase)ytoluene$$     $$=$$  ptoluenePtotal   $$=$$  $$370.51190.5$$  $$+$$  $$370.5$$  $$=$$  $$0.237$$

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