Total charge required for the oxidation of two moles Mn3O4 into MnO42- in presence of alkaline medium is :

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5 F

10 F

20 F

None of these

answer is C.

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Detailed Solution

1 mole Mn3O4, lose 6−83×3=10 mole e- ; so total charge required = 2 x 10 ⇒ 20 F

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