Q.

The total number of atoms of all elements present in 1 mole of ammonium dichromate is

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answer is 3.

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Detailed Solution

1mol NH42Cr2O7=Total no. of atoms ×6.023×1023=19 atoms (=2N+8H+2Cr+7O=19)×6.023×1023 =114.437×1023 atoms
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The total number of atoms of all elements present in 1 mole of ammonium dichromate is