Total number of cyclic optical isomers possible with the formula, C5H10 is ‘X’. Total number of terminal alkenes(structural only) possible with the formula, C5H10 is ‘Y’. Difference between X and Y is

(1)Number of structurally isomeric alkenes = 5 ;(2)Number of structurally isomeric cycloalkanes = 5 ;(3)Number of structural isomers = 10 ;(4)Number of acyclic stereo isomers = 2 ;cis 2-pentene and trans 2-pentene ;(5)Number of cyclic stereo isomers = 3 ;cis 1,2-dimethyl cyclopropane(meso) and trans 1,2-dimethyl cyclopropane(d and l) ;(5)Number of stereoisomers = 5 ;(6)Number of acyclic isomers = 6 ;(7)Number of cyclic isomers = 7 ;(8)Total number of isomers =13 ;