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Q.

Total number of nuclides which are β⊕ emitter are:I.    20Ca49 II.    80Hg195 III.    5B8 IV.   67Ho150 V.   13Al30 VI.  36Kr39

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answer is 3.

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Detailed Solution

β⊕-emitter ⇒ II. 80Hg195  III. 5B8 IV67Ho150 II. 80Hg195,np=11580=1.43 n/p is lower than the  stability belt for Hgn/p should be equal  to 1.53n/p is lower than 1.53, so it will emit β⊕ to increase n/p ratio III. 5B8,np=35=0.6,  (for stability n/p=1 ). n/p is lower than 1. Z up to 20,np=1. It is β⊕ emitter, IV. 67Ho150,np=3367=1.3⋅ For stability with Z>60,n/p should be 1.50. n/p is lower than 1.5. So β⊕ emitter.
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