Total number of optical isomers (alkadienes only) possible with the formula, C5H8 is

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answer is C.

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Detailed Solution

Total number of alkadienes (structural and stereo) = 8 ;Number of structurally isomeric alkadienes = 6 ;Number of structurally isomeric conjugated alkadienes = 2 ;Number of structurally isomeric cumulative alkadienes = 3 ;Number of structurally isomeric isolated alkadienes = 1 ;Number of structurally isomeric straight chain alkadienes = 4 ;Number of structurally isomeric branched chain alkadienes = 2 ;Number of stereo isomers (alkadienes only) = 4 ;Number of geometrical isomers (alkadienes only) = 2 ;Number of optical isomers (alkadienes only) = 2 ;Number of enantiomeric pairs (alkadienes only) = 1 ;Number of structurally isomeric straight chain pentadienes = 4 ;Number of structurally isomeric branched chain butadienes = 2 ;Number of structurally isomeric branched chain propdienes = 0 ;*Cumulative dienes of the type (XY)C=C=C(XY) or (AB)C=C=C(XY) are dissymmetric.They exhibit optical isomerism ;Ex : 2,3-pentadiene…(XY)C=C=C(XY) type where X = H , Y = CH3 :

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