The total number of oxidation states shown by nitrogen is :

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answer is D.

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Detailed Solution

NH3→(−3),H2N−NH2→(−2),H2N−O−H→(−1),HN3( hydrazoicacid )→−13, N2→(0),N2O→(+1),NO→(+2),N2O3→(+3),NO2→(+4)N2O5→(+5). Total 10 oxidationstates.

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