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Q.

The total number of possible isomers of the complex compound [CuII(NH3)4][PtIICl4] is

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a

3

b

6

c

5

d

4

answer is D.

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Detailed Solution

For [CuII(NH3)4][PtIICl4]. four isomers are possible which are [Cu(NH3)4] [PtCl4], [CuCl4] [Pt(NH3)4] , [PtCl3(NH3)] [Cu(NH3)3Cl] and [Pt(NH3)3Cl] [Cu(NH3)Cl3]

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