First slide

Isomerism

Question

The total number of possible isomers of the complex compound $[{Cu}^{11} {({NH}_{3})}_{4}] [{Pt}^{11} {Cl}_{4}]$ is

Easy

A

3
B

6
C

5
D

4

Solution

The possible isomers of the complex are
$\begin{array}{l} [Cu {({NH}_{3})}_{3} Cl] [{PtCl}_{3} {NH}_{3}] \\ [Cu ({NH}_{3}) {Cl}_{3}] [Pt {({NH}_{3})}_{3} Cl] \\ [{CuCl}_{4}] [Pt {({NH}_{3})}_{4}] \end{array}$
The total number of isomers is four.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App