Q.
The total number of protons in 10 g of calcium carbonate is N0=6.023×1023
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a
1.5057×1024
b
2.0478×1024
c
3.0115×1024
d
4.0956×1024
answer is C.
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Detailed Solution
∵100gmrCaCO3=6.023×1023 molecules∴10gn3CaCO3=6.023×1023100×10=6023×1022 molecule1 molecule of CaCO3−50 protons6.023×1022 molecule of CaCO3=50x6.023x1022=3.0115x1024
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