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Q.

The total number of protons in 10 g of calcium carbonate is N0=6.023×1023

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a

1.5057×1024

b

2.0478×1024

c

3.0115×1024

d

4.0956×1024

answer is C.

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Detailed Solution

∵100gmrCaCO3=6.023×1023 molecules∴10gn3CaCO3=6.023×1023100×10=6023×1022 molecule1 molecule of CaCO3−50 protons6.023×1022 molecule of CaCO3=50x6.023x1022=3.0115x1024
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