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Q.

Total number of structurally isomeric primary alcohols possible with the formula, C4H10O is ‘X'. Total number of structurally isomeric unsymmetrical ethers possible with the formula, C4H10O is ‘Y’. Difference between X and Y is

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a

3

b

2

c

1

d

0

answer is D.

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Detailed Solution

Total number of isomers (structural and stereo) = 8 ;Total number of structural isomers = 7 ;Total number of stereo isomers  = 2 ;Total number of enantiomeric pairs = 1 ;Total number of alcohols (structural and stereo) = 5 ;Total number of structurally isomeric alcohols = 4 ;Total number of structurally isomeric primary alcohols = 2 ;Total number of structurally isomeric secondary alcohols = 1 ;Total number of structurally isomeric tertiary alcohols = 1 ;Total number of structurally isomeric straight carbon chain alcohols = 2 ;Total number of structurally isomeric branched carbon chain alcohols = 2 ;Total number of stereo isomers (alcohols only) = 2 ;Total number of enantiomeric pairs (alcohols only) = 1 ;Total number of ethers (structural and stereo) = 3 ;Total number of structurally isomeric ethers = 3 ;Total number of stereo isomers (ethers only) = 0 ;Total number of enantiomeric pairs (ethers only) = 0 ;
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Total number of structurally isomeric primary alcohols possible with the formula, C4H10O is ‘X'. Total number of structurally isomeric unsymmetrical ethers possible with the formula, C4H10O is ‘Y’. Difference between X and Y is