Total number of sulphate ions present in 3.92g of chromic sulphate is (Cr = 52, S=32, O=16)

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1.8×1022

1.8×1023

1.2×1021

6×1023

answer is A.

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Detailed Solution

Chromic Sulphate = Cr2(SO4)3GFW of Cr2(SO4)3 = 392gCr2(SO4)3 2Cr+3 + 3SO4-2 Number of Sulphate ions(X) =

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