Q.

The total number of valence electrons in 4.2 g of N3− ion is (NA is the Avogadro's number)

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a

1.6 NA

b

3.2 NA

c

2.1 NA

d

4.2 NA

answer is A.

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Detailed Solution

42g  of  N3-  ions  has  16NA  valence  electrons;4.2g of N3- have  =16NA42 ×  4.2  =  1.6  NA.
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