Q.
The total number of valence electrons in 4.2 g of N3− ion is (NA is the Avogadro's number)
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a
1.6 NA
b
3.2 NA
c
2.1 NA
d
4.2 NA
answer is A.
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Detailed Solution
42g of N3- ions has 16NA valence electrons;4.2g of N3- have =16NA42 × 4.2 = 1.6 NA.
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