The total surface area of a cube of edge length 2 cm is 12×10-16 and the total surface area of the same material if it were subdivided into colloidal size cubes, each having an edge length of l0-8 cm is 12×10x. The value of x is___

Surface area of cube of edge length 1 cm - 6 × 2 cm2Surface area of cube of edge length 2 × l0-8 cm=12×10−16cm2Let n cubes of 12 × 10-16 cm2 are present on breaking the cube of 6 cm2∴n× volume of cube of edge length 10−8cm= volume of cube of edge length 2 cm.n×43×π×10−83=43×π×(2)3∴n=8×10+24New total surface area∴=1024×12×10−16=12×108