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Q.

Total vapour pressure of mixture of 1 mole of volatile component A (PBo =100 mm Hg) and 3 mole of volatile component B (PBo =80 mm Hg) is 90 mm HS For such case:

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a

there is positive deviation from Raoult's 1aw

b

boiling point has been lowered

c

force of attraction between A and B is smaller than that between A and A or between B and B

d

all the above statements are correct

answer is D.

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Detailed Solution

Pideal =PA∘xA+PB∘xB =100×14+80×34⇒85mmHgPactual =90mmHg;∵Actual v. pr. is greater tian ideal solution v. pr. so +ve deviation from Raoult's law.
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Total vapour pressure of mixture of 1 mole of volatile component A (PBo =100 mm Hg) and 3 mole of volatile component B (PBo =80 mm Hg) is 90 mm HS For such case: