Total vapour pressure of mixture of 1 mole of volatile component A (PBo =100 mm Hg) and 3 mole of volatile component B (PBo =80 mm Hg) is 90 mm HS For such case:
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a
there is positive deviation from Raoult's 1aw
b
boiling point has been lowered
c
force of attraction between A and B is smaller than that between A and A or between B and B
d
all the above statements are correct
answer is D.
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Detailed Solution
Pideal =PA∘xA+PB∘xB =100×14+80×34⇒85mmHgPactual =90mmHg;∵Actual v. pr. is greater tian ideal solution v. pr. so +ve deviation from Raoult's law.
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Total vapour pressure of mixture of 1 mole of volatile component A (PBo =100 mm Hg) and 3 mole of volatile component B (PBo =80 mm Hg) is 90 mm HS For such case: