The total vapour pressure of a 4 mole% solution of NH3 in water at 293k is 50.0torr. The vapour pressure of pure water is 17.0 torr at this tempe-rature. Applying Henry’a law and Raoult’s laws, calculate the total vapour pressure for 5mole% solution

At 293K ,            Total V.P of 4mole% sol. of NH3 in water=50torr           V.P of pure water = 17 torr         V.P of pure NH3 = (50 - 17)=33torr     Total V.P of  5mole% sol. of NH3 in water = ?By comparing 4 mole% and 5mole% NH3 sol.  According to Henry's lawAt constant Temperature , KH  is constant temperature remains constant, will be a constantTotal VP of 5 mole% NH3 sol. in water=                                                      = (41.25+17)torr = 58.25 torr