Total volume occupied by a mixture containing 1 equivalent each of N2, H2 and NH3 based on the following equation at STP isN2(g)+3H2(g)⟶2NH3(g)

N2≡3H2≡6H Thus, equivalent mass of N2= Molar mass 6Volume occupied by I equivalent N2 at STP =22.46LNH2 ≡ 3HThus, equivalent mass of NH3 at STP =22.43LH2 ≡ 2H Thus, equivalent mass of H2= Molar mass 2 Volume occupied by 1 equivalent H2 gas at STP =22.42L Thus, total volume =VN2+VNH3+VH2=22.46+22.43+22.42=22.46+2×22.46+3×22.46=22.4L