In transforming 0.01 mole of PbS to PbSO4, the volume of 10 volume H2O2 required is
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a
11.2 ml
b
22.4 ml
c
44.8 ml
d
33.6 ml
answer is C.
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Detailed Solution
PbS+4H2O2→PbSO4+4H2O 4H2O2→4H2O+2O2 Volume of O2 at STP = Volume in ml x volume strength Volume in ml=Volume of O2 at STPvolume strength =0.01×2×22.4×100010=44.8 ml