Derivatives of carbonyl compounds

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Treatment of compound O with $K M n O_{4} / H^{+}$ gave P, which on heating with ammonia gave Q. The compound Q on treatment with $B r_{2} / N a O H$ produced R. On strong heating, Q gave S, which on further treatment with ethyl 2-bromopropanoate in the presence of KOH followed by acidification, gave a compound T.

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The compound R is

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Question

The compound T is

Solution

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COLUMN - I Reaction		COLUMN - II Product
a.	$\begin{aligned} (COOH)_{2} \cdot 2 H_{2} O \frac{Δ}{105^{\circ} C} \to \\ (I) \end{aligned}$	p.	$2 {CO}_{2} + H_{2} O$
b.	$\begin{aligned} (I) \frac{Δ at 200^{\circ} C}{or} → \\ H_{2} {SO}_{4}, at 90^{\circ} C \end{aligned}$	q.	$(COOH)_{2}$
c.		r.	$CO + {CO}_{2} + H_{2} O$
d.	$(I) \frac{Δ}{{KMnO}_{4}}$	s.	Carbon suboxide $(O = C = C = C = O)$
e.	$2 HCOONa \frac{Δ, 360^{\circ} C}{H_{3} O^{\oplus}}$	t.	$MeCOOH + {CO}_{2}$
f.

Derivatives of carbonyl compounds

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Treatment of compound O with KMnO4/H+ gave P, which on heating with ammonia gave Q. The compound Q on treatment with Br2/NaOH produced R. On strong heating, Q gave S, which on further treatment with ethyl 2-bromopropanoate in the presence of KOH followed by acidification, gave a compound T.

The compound R is

The compound T is

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