On treatment of $$PtNH342+$$ with concentrated HCl, two compounds (I) and (II) having the same formula, $$PtNH32Cl2$$ are obtained, (I) can be converted into (II) by boiling with dilute HCl. A solution of (I) reacts with oxalic acid to form $$PtNH32C2O4$$ whereas (II) does not react. Point out the correct statement of the following.

Question

On treatment of $$PtNH342+$$ with concentrated HCl, two compounds (I) and (II) having the same formula, $$PtNH32Cl2$$ are obtained, (I) can be converted into (II) by boiling with dilute HCl. A solution of (I) reacts with oxalic acid to form $$PtNH32C2O4$$ whereas (II) does not react. Point out the correct statement of the following.

Infinity Learn · Accepted Answer

Chelate ligands i.e. oxalato being too small to span the transpositions and thus prefer to occupy the $$cis-position$$. So (I) is cis and (II) is trans. Platinum is in $$+2$$ oxidation state with $$5d8$$ valence shell electron configuration. This configuration has higher CFSE and thus favours square planar geometry.

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