Two amperes of current is passed through acidulated water for ‘t’ seconds to decompose 18 grams of water .  Value of ‘t’ is equal to

At  anode 2H2O→4H++4e-+O2At  cathode [2H2O+2e-→H2+2OH-]×2Net   reaction 2H2O→4F2H2+O236g       H2O      require       4F 18g        H2O     require       2F Q=it 2×96500=2×t t=96500 seconds