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Q.

Two Faraday of electricity is passed through a solution of CuSO4. The mass of copper deposited at the cathode is (atomic mass of Cu = 63.5 u)

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a

0 g

b

63.5 g

c

2 g

d

127 g

answer is B.

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Detailed Solution

Given, Q - 2F, Atomic mass of Cu - 63.5 uValency of the metal  Z = 2We have, CuSO4⟶Cu2++SO42              Cu2+1mol+2e−2mol⟶Cu1mol=63.5gAlternatively,  w=zQ=EF⋅2F=2E=2×63.52=63.5g
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