Two gases A and B having the molar mass 60 and 45 g mol-1, respectively are enclosed in a vessel. The weight of A is 0.5 g and that of B is 0.2 g. The total pressure of the mixture is 750 mm. The partial pressure of gas A and B respectively are

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260 mm,490 mm

l90mm, 560 mm

490 mm, 260 mm

520 mm, 290 mm

answer is C.

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Detailed Solution

Number of moles of A = 0.5060=0.0083Number of moles of B =0.2045=0.0044 Total pressure =750 mm of HgpA= mole fraction of A× total prelssure =0.00830.0083+0.0044×750=490 mmpB=750-490=260 mm

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