Two gases X and Y having molecular weights 60 g mol- and 45 g mol- respectively were enclosed in a vessel. If weight of X is 0.5 g and that of Y is 0.2 g, calculate the partial pressure of the two gases, if total pressure of mixture is 750 mm.
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a
490.16; 259.84
b
480.25 ; 240.3
c
250.3; 480.16
d
720.2.; 520.11
answer is A.
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Detailed Solution
no. of mol. of X=0.560=8.3×10−3no. of mol. of Y=0.245=4.4×10−3Total no. of mol. =8.3×10−3+4.4×10−3=12.7×10−3Total pressure =750mmPx=8.3×10−312.7×10−3×750=490.16mm;Py=4.4×10−312.7×10−3×750 =259.84mm