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Q.

Two glucose solutions are mixed. One has a volume of 480 mL and a concentration of 1.50 M and the second has a volume of 520 mL and concentration 1.20 M. The  molarity of final solution is

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a

1.20 M

b

1.50 M

c

1.344 M

d

2.70 M

answer is C.

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Detailed Solution

M1V1+M2V2=M3V3V3=V1+V21.5×480+1.2×520=M3×1000M3=1.344M
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