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Q.

Two hybrid orbitals have a bond angle of 120°. The percentage of s-character in the hybrid orbital is nearly

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a

25%

b

33%

c

50%

d

66%

answer is B.

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Detailed Solution

cos⁡θ=ss−1=cos⁡120∘=−1/2ss−1=−0.5; s=−0.5s+0.51.5s=0.5s=1/3=33.33%
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