Two liquids A and B from ideal solutions. At 300 K, the vapour pressure of solution containing 1 mole of A and 3 mole of B is 550 mm Hg. At the same temperature, if one more mole of B is added to this solution, the vapour pressure of the solution increases by 10 mm H8. Determine the vapour pressure of A and B in their pure states (in mm Hg):
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a
400, 600
b
500, 500
c
600, 400
d
None of these
answer is A.
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Detailed Solution
Since, P=XAPA∘+XBPB∘,we have 11+3PA∘+31+3PB∘=550 mm Hg 11+4PA∘+41+4PB∘=560 mm Hg That is 0.25PA∘+0.75PB∘=550 mm Hg 0.20 PA∘+0.8PB∘=560 mm Hg Solving for Pj and PBo, we get; PA∘=400 mm Hg and PB∘=600 mm Hg