Two liquids A and B from ideal solutions. At $$300$$ K, the vapour pressure of solution containing $$1$$ mole of A and $$3$$ mole of B is $$550$$ mm Hg. At the same temperature, if one more mole of B is added to this solution, the vapour pressure of the solution increases by $$10$$ mm $$H8$$. Determine the vapour pressure of A and B in their pure states (in$$ mm $$Hg):

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Infinity Learn · Accepted Answer

Since, $$P=XAPA$$∘$$+XBPB$$∘,we have  $$11+3PA$$∘$$+31+3PB$$∘$$=550$$ mm Hg $$11+4PA$$∘$$+41+4PB$$∘$$=560$$ mm Hg That is $$0.25PA$$∘$$+0.75PB$$∘$$=550$$ mm Hg               $$0.20$$ PA∘$$+0.8PB$$∘$$=560$$ mm Hg Solving for Pj and PBo, we get; PA∘$$=400$$ mm Hg and PB∘$$=600$$ mm Hg

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