Two matter waves A and B have same magnitude of mass. If wavelength of B is twice that of B then the velocity of A must be ……

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Twice that of B

Half of that of B

Same as that of B

One fourth of that of B

answer is A.

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Detailed Solution

λ=hmv; Given mA=mB; Thus λAvA=λBvB since h is a constant. 1×vA=2×vB

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