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Q.

Two mole of an ideal gas Cv=12.5JK−1mol−1 occupy a volum e of 2 dm3 at 300 K. If it is heated to 320 K to increase the volume to 4 dm3 the entropy change is

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a

11.5

b

8.3

c

13.1

d

9.3

answer is C.

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Detailed Solution

ΔS=nCvIn⁡T2T1+nRIn⁡V2V1=2×12.5×2.303log⁡320300+2×8.314×2.303log⁡42=1.6+11.5=13.1JK−1mol−1
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