Two oxides of a metal contain 50% and 40% metal M respectively. If the formula of the first oxide is MO2, theformula of the second oxide will be

First oxide               Second oxideM    50%                   M = 40%O    50%                    Formula = ?Let the atomic weight of metal = x∴ % of M in MO2 = 1×x×100x+32=50 (given)Hence x = 32∴ Empirical formula of second oxide:O=6016=3.75 M=4032=1.25                3.751.25=31.251.25=1Thus, the formula of second oxide = MO3