Two Pi and half sigma bonds are present in:

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O2+

N2+

answer is D.

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Detailed Solution

Explanation:3) O2→Bond Order→2→1 σ and 1 π2)N2→Bond Order→3→1 σ and 2 π1)O2 +→Bond Order→2.5→1 σ and 1.5 π4)N2+→Bond Order→2.5→12 σ and 2π

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