Two reactions A→products and B→products have rate constant, ka and kb respectively at temperature T and activation energies are Ea and Eb respectively. If ka>kb and Ea
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a
on increasing temperature ka will be greater than kb
b
At lower temperature ka and kb will differ more
c
As temperature rises ka and kb will be close to each other in magnitude
d
All of the above are correct
answer is D.
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Detailed Solution
lnka=lnA−Ea/RT; lnkb=lnA−Eb/RTAs temperature rises E/RT become negligible.