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Two salts A2X and MX have the same value of solubility production of 4.0×10−12. The ratio of their molar solubilities i.eSA2XS(MX). =…(Round off the nearest integer).

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answer is 50.

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Detailed Solution

For AX24s3=4×10−12⇒S1=10−123S1=10−4MFor MXS22=4×10−12S2=2×10−6S1S2=10−42×10−6=1002=50

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